Hardin is located at 39°16'11" North, 93°49'60" West (39.269616, -93.833245)1.
According to the United States Census Bureau, the city has a total area of 1.6 km² (0.6 mi²). 1.6 km² (0.6 mi²) of it is land and none of it is covered by water.
As of the census of 2000, there are 614 people, 247 households, and 170 families residing in the city. The population density is 382.4/km² (992.0/mi²). There are 267 housing units at an average density of 166.3/km² (431.4/mi²). The racial makeup of the city is 97.39% White, 0.16% African American, 1.14% Native American, 0.16% Asian, 0.00% Pacific Islander, 0.33% from other races, and 0.81% from two or more races. 0.33% of the population are Hispanic or Latino of any race.
There are 247 households out of which 34.4% have children under the age of 18 living with them, 56.7% are married couples living together, 7.7% have a female householder with no husband present, and 30.8% are non-families. 27.5% of all households are made up of individuals and 17.8% have someone living alone who is 65 years of age or older. The average household size is 2.49 and the average family size is 3.04.
In the city the population is spread out with 28.5% under the age of 18, 8.6% from 18 to 24, 28.0% from 25 to 44, 19.7% from 45 to 64, and 15.1% who are 65 years of age or older. The median age is 36 years. For every 100 females there are 102.0 males. For every 100 females age 18 and over, there are 96.0 males.
The median income for a household in the city is $35,000, and the median income for a family is $40,729. Males have a median income of $30,809 versus $17,500 for females. The per capita income for the city is $14,676. 6.1% of the population and 7.9% of families are below the poverty line. Out of the total people living in poverty, 3.5% are under the age of 18 and 11.3% are 65 or older.
Source | Copyright